Hints : Apply Euler Totient Function Rule
f(n) = n*[(1-(1/p1))*(1-(1/p2))*..........(1-(1/pk))]
#include <bits/stdc++.h>
using namespace std;
#define n 1000005
bool a[n];
long long int k=2;
long long int twin[n];
void sieve()
{
long long int i,j;
a[0]=a[1]=1;
for(i=4;i<=n;i=i+2)
{
a[i]=1;
}
for(i=3;i<=sqrt(n);i=i+2)
{
for(j=i*i;j<=n;j=j+2*i)
{
a[j]=1; //3*3, 3*5,3*7.....
}
}
twin[1]=2;
for(i=3;i<=n;i=i+2)
{
if(a[i]==0)
{
twin[k]=i;
k++;
}
}
}
int main()
{
long long int b,x,l,g,m,t=0,q;
long double c,r,p;
sieve();
//freopen("10179in.txt","r",stdin);
//freopen("10179out.txt","w",stdout);
while(cin>>m)
{
t++;
b=0;
q=m;
if(m==0)
{
break;
}
r=1.0;
for(g=1;g<=k && twin[g]<=sqrt(m);g++)
{
c=0;
p=twin[g];
if(m%twin[g]==0)
{
while(m%twin[g]==0)
{
c++;
m=m/twin[g];
if(m==0 || m==1)
{
break;
}
}
r=r*(1-(1/p));
}
}
if(m>1)
{
r=r*(1-(1/(double)m));
}
cout<<setprecision(10)<<q*(double)r<<endl;
}
return 0;
}
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